19/11/2010, 19:06
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| | Fecha de Ingreso: octubre-2010 Ubicación: Edo. de México
Mensajes: 94
Antigüedad: 14 años, 2 meses Puntos: 9 | |
Respuesta: how could I obtain the same result like with StringTokenizer in Java [strt
Código:
DESCRIPTION
This interface is obsoleted by strsep(3).
The strtok() function is used to isolate sequential tokens in a null-ter-
minated string, str. These tokens are separated in the string by at
least one of the characters in sep. The first time that strtok() is
called, str should be specified; subsequent calls, wishing to obtain fur-
ther tokens from the same string, should pass a null pointer instead.
The separator string, sep, must be supplied each time, and may change
between calls.
The implementation will behave as if no library function calls strtok().
The strtok_r() function is a reentrant version of strtok(). The context
pointer last must be provided on each call. The strtok_r() function may
also be used to nest two parsing loops within one another, as long as
separate context pointers are used.
The strtok() and strtok_r() functions return a pointer to the beginning
of each subsequent token in the string, after replacing the token itself
with a NUL character. When no more tokens remain, a null pointer is
returned.
EXAMPLES
The following uses strtok_r() to parse two strings using separate con-
texts:
char test[80], blah[80];
char *sep = "\\/:;=-";
char *word, *phrase, *brkt, *brkb;
strcpy(test, "This;is.a:test:of=the/string\\tokenizer-function.");
for (word = strtok_r(test, sep, &brkt);
word;
word = strtok_r(NULL, sep, &brkt))
{
strcpy(blah, "blah:blat:blab:blag");
for (phrase = strtok_r(blah, sep, &brkb);
phrase;
phrase = strtok_r(NULL, sep, &brkb))
{
printf("So far we're at %s:%s\n", word, phrase);
}
}
source: man 3 strtok
everytime you need info about a particular command/function check his man page. If u are under linux/unix/mac just type "man <section> <command/function>" where section is the number of the section you want to check out (section 3 goes for system calls and functions i think).
I hope my answer helped you
Greetings++ |