Codigo
Código:
$query = "SELECT * FROM game ORDER BY id_game desc LIMIT 0,10";
$ress = mysql_query($query);
while ($dato = mysql_fetch_array($ress)) {
$original = imagecreatefromjpeg('"swf/'.$dato[photo].'"');
$thumb = imagecreatetruecolor(150,150);
$ancho = imagesx($original);
$alto = imagesy($original);
imagecopyresampled($thumb,$original,0,0,0,0,150,150,$ancho,$alto);
imagejpeg($thumb,'swf/$dato[photo]',90);
echo '<a href="juegos.php?cod='.$dato[id_game].'"><h3>'.$dato[game].'</h3></a><br>';
echo '<img src="swf/'.$dato[photo].'"><br><br>';
}
Pero que pasa me da este error:
Warning: imagecreatefromjpeg("swf/ninjapiro.jpg") [function.imagecreatefromjpeg]: failed to open stream: No such file or directory in /home/divertig/public_html/index.php on line 28
Warning: imagesx(): supplied argument is not a valid Image resource in /home/divertig/public_html/index.php on line 30
Warning: imagesy(): supplied argument is not a valid Image resource in /home/divertig/public_html/index.php on line 31
Warning: imagecopyresampled(): supplied argument is not a valid Image resource in /home/divertig/public_html/index.php on line 32
Alguien me podria ayudar a arreglar esto :S
