Código PHP:
<?php
//Actualiza la opción
$sql = "UPDATE CHOICE SET CHOICE_TEXT=" . $HTTP_GET_VARS["CHOICE_TEXT"] . " WHERE CHOICE_ID=" . $HTTP_GET_VARS["CHOICE_ID"];
$result = mysql_query( $sql )
or die("Bad query: " . mysql_error());
?>
Código PHP:
<?php
$sql = "DELETE FROM CHOICE WHERE CHOICE_ID=" . $HTTP_GET_VARS["CHOICE_ID"];
$result = mysql_query( $sql )
or die("Bad query: " . mysql_error());
//delete all answers with this choice
$sql = "DELETE FROM ANSWER WHERE CHOICE_ID=" . $HTTP_GET_VARS["CHOICE_ID"];
$result = mysql_query( $sql )
or die("Bad query: " . mysql_error());
?>
P.D. este es el error que me manda:
Cita:
Bad query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Select 2z WHERE CHOICE_ID=499' at line 1