Por mientras les dejo estas 2
Código PHP:
$clasificacion=$_POST['sel'];
switch($clasificacion)
{
case 1:
$fecha= time() + (1 * 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 2:
$fecha= time() + (2 * 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 3:
$fecha= time() + (3 * 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 4:
$fecha= time() + (4* 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 5:
$fecha= time() + (5* 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 6:
$fecha= time() + (6* 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 7:
$fecha= time() + (724 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
case 8:
$fecha= time() + (8 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
default:
$fecha= time() + (0* 24 * 60 * 60);
echo date("d/m/Y", $fecha);
break;
}
?>
a la fecha actual
Código PHP:
<?php
//The function returns the no. of business days between two dates and it skeeps the holidays
function getWorkingDays($startDate,$endDate,$holidays){
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = (strtotime($endDate) - strtotime($startDate)) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N",strtotime($startDate));
$the_last_day_of_week = date("N",strtotime($endDate));
//The two can't be equal because the $no_remaining_days (the interval between $the_first_day_of_week and $the_last_day_of_week) is at most 6
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week < $the_last_day_of_week){
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else{
if ($the_first_day_of_week <= 6) $no_remaining_days--;
//In the case when the interval falls in two weeks, there will be a Sunday for sure
$no_remaining_days--;
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
$workingDays = $no_full_weeks * 5 + $no_remaining_days;
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if (strtotime($startDate) <= $time_stamp && $time_stamp <= strtotime($endDate) && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
//Example:
$holidays=array("2006-12-25","2006-12-26","2007-01-01");
echo getWorkingDays("2007-08-01","2007-08-31",$holidays)
// => will return 8
?> Si mejoran los scripts los publican porfavor para todos aprender
