Código PHP:
mysql_fetch_array(): supplied argument is not a valid MySQL
result resource in mysql_fetch_array():
supplied argument is not a valid MySQL result resource in
Código PHP:
<?php
$var = $row_Recordset1['Maximo'];
mysql_select_db($database_, $);
$maximostatus = mysql_query("SELECT status_2
FROM provider_call_log WHERE provider_call_log_id = $var ");
if( $rs = mysql_fetch_array( $maximostatus , MYSQL_ASSOC )
)
{
echo $rs["status_2"];
}
else
//(!$rs)
{
echo "Without Calls ";
}
?>