Código PHP:
<td height="105" colspan="2" valign="top"><table width="100%" border="0" cellpadding="0" cellspacing="0">
<!--DWLayoutTable-->
<tr>
<td width="81" height="105" valign="top"><table width="100%" border="0" cellpadding="0" cellspacing="0">
<!--DWLayoutTable-->
<tr>
<td width="81" height="105"><a href="inicio.php"><onmouseover="image0.src='mouseover_on_1.gif';"
onmouseout="image0.src='mouseover_off_1.gif';"><img name="image0"
src="mouseover_off_1.gif" border="0" width="119" height="25"></a></td>
</tr>
</table></td>
<td width="171" valign="top"><table width="100%" border="0" cellpadding="0" cellspacing="0">
<!--DWLayoutTable-->
<tr>
onmouseout="image0.src='mouseover_off_1.gif';">
Hay alguna forma de arreglarlo asi como esta? o tendría que volver a hacer la parte de los botones?
El codigo del mouseovver que uso es este:
Código PHP:
<script language="JavaScript">
<!--
// Comienzo del código
// Especificamos las imágenes primarias
image0 = new Image();
image0.src = "mouseover_off_1.gif";
image1 = new Image();
image1.src = "mouseover_off_2.gif";
image2 = new Image();
image2.src = "mouseover_off_3.gif";
// Fin del código
-->
</script>
Código PHP:
<a href="enlace.htm" onmouseover="image0.src='mouseover_on_1.gif';"
onmouseout="image0.src='mouseover_off_1.gif';"><img name="image0"
src="mouseover_off_1.gif" border="0" width="119" height="25"></a>
<a href="enlace.htm" onmouseover="image1.src='mouseover_on_2.gif';"
onmouseout="image1.src='mouseover_off_2.gif';"><img name="image1"
src="mouseover_off_2.gif" border="0" width="119" height="25"></a>
<a href="enlace.htm" onmouseover="image2.src='mouseover_on_3.gif';"
onmouseout="image2.src='mouseover_off_3.gif';"><img name="image2"
src="mouseover_off_3.gif" border="0" width="119" height="25"></a>