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Código Python:
Ver originalimport numpy as np
import matplotlib.pyplot as plt
ki=222.2*10**3
km=62.5*10**3
mui=166.67*10**3
mum=28.85*10**3
fi=0.25
J=np.matrix([[1./3.,1./3.,1./3.,0,0,0],[1./3.,1./3.,1./3.,0,0,0],[1./3.,1./3.,1./3.,0,0,0],[0,0,0,0,0,0],[0,0,0,0,0,0],[0,0,0,0,0,0]])
I=np.identity(6)
K=I-J
x=1.
sigmaeqold=0.
mumsec=mum
STRESS=[]
STRAIN=[]
E=1*10**5
for a in range (401): #from 0 to 400
sigma0=np.matrix([[a],[0.],[0.],[0.],[0.],[0.]])
STRESS.append(a)#en Mpa
while x< E :
k=km+fi*(ki-km)/(1.+(1.-fi)*(ki-km)/((3.*km+4.*mumsec)/3.))
mu=mumsec+fi*(mui-mumsec)/(1.+(1.-fi)*(mui-mumsec)/((5./3.*(3.*km+4*mumsec)/(km*2*mumsec)/2)))
Msecm=(1./(3.*km))*J+(1./(2.*mum))*K #<--(HERE IS THE SYNTAX ERROR)
Msec=(1./(3.*k))*J+(1./(2.*mu))*K
Mi=(1./(3.*ki))*J+(1./(2.*ki))*K
INV=np.linalg.inv(Msecm-Mi)
Bsecm=(1./(1-fi))*(INV-(Msec-Mi))
sigmam=Bsecm*sigma0
matrixnumber=sigmam.T*sigmam
number=float(matrixnumber)# just for making a float number from a matrix 1x1
sigmaeq= (3./2.)*(number)**0.5
mu_msec=sigmaeq/((sigmaeq/mum)+3.*(sigmaeq/400.)**(1./0.15))
x=sigmaeq-sigmaeqold
sigmaeqold=sigmaeq
strain=Msec*sigma0
strainlist=list(strain)
strainpop=strain.pop(1)
strainvalue=float(strainpop)
STRAIN.append(strainvalue)
plt.plot(STRAIN,STRESS)