Como sacar informacion de un XML que esta en otra URL

[xSkArx]

Otra vez con lo mismo,

Iniciado por andresdzphp

Puedes hacer algo así:

Código PHP:

<?php
 
$source = '<scores>
<game time="Nov 7 2013 05:30:00:000PM">
<sport id="1" name=""/>
<league id="1" name=""/>
<away number="107" name="Washington" abbr="WAS" score="" points="-1" price="-106" ML="-111" opener_points="-1" opener_price="-120" opener_ML="-132"/>
<home number="108" name="Minnesota" abbr="MIN" score="" points="1" price="-104" ML="101" opener_points="1" opener_price="109" opener_ML="120"/>
<status time_remaining="" value=""/>
<total points="48.5" over="-102" under="-108" opener_total="48" opener_over="-105" opener_under="-105"/>
</game>
<game time="Nov 7 2013 04:30:00:000PM">
<sport id="1" name=""/>
<league id="2" name=""/>
<away number="109" name="Oklahoma" abbr="OKL" score="" points="17" price="-112" ML="526" opener_points="14" opener_price="-106" opener_ML="481"/>
<home number="110" name="Baylor" abbr="BAY" score="" points="-17" price="100" ML="-665" opener_points="-14" opener_price="-106" opener_ML="-600"/>
<status time_remaining="" value=""/>
<total points="74" over="-108" under="-104" opener_total="72.5" opener_over="-106" opener_under="-106"/>
</game>
</scores>';
 

Código PHP:

$doc = new DOMDocument();
$doc->preserveWhiteSpace = false;
$doc->loadXML($source);
$games = $doc->getElementsByTagName('game');
 
foreach ($games as $game) {
    foreach ($game->childNodes as $child) {
        echo "<h3>$child->nodeName</h3>";
        if ($child->hasAttributes()) {
            foreach ($child->attributes as $attr) {
                echo "<p>Atributo: $attr->nodeName // Valor: $attr->nodeValue</p>";
            }
        }
    }
    echo '<hr />';
}
 

Ya sólo tendrías que armar la tabla.

Saludos.