capturar el valor de un colorpicker,

[fcosun]

hola, como puedo capturar el valor de un colorpicker, a traves de div ? o se hace de otra forma.

para guardarlo en mysql.

aca tengo el codigo

Código PHP:

<link rel="stylesheet" href="css/colorpicker.css" type="text/css" />
<link rel="stylesheet" media="screen" type="text/css" href="css/layout.css" />
<title>ColorPicker - jQuery</title>
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/colorpicker.js"></script>
<script type="text/javascript" src="js/eye.js"></script>
<script type="text/javascript" src="js/utils.js"></script>
<script type="text/javascript" src="js/layout.js?ver=1.0.2"></script>
 
<script type="text/javascript">
$('#colorpickerField1, #colorpickerField2, #colorpickerField3').ColorPicker({
    onSubmit: function(hsb, hex, rgb, el) {
        $(el).val(hex);
        $(el).ColorPickerHide();
    },
    onBeforeShow: function () {
        $(this).ColorPickerSetColor(this.value);
    }
})
.bind('keyup', function(){
    $(this).ColorPickerSetColor(this.value);
});
</script>
    
<script type="text/javascript">
function notEmpty(){
    var myTextField = document.getElementById('colorpickerField1');
    if(myTextField.value != "")
        alert("You entered: " + myTextField.value)
    else
        alert("Would you please enter some text?")      
}
</script>
 
 
<?php
 
echo "<div id=\"colorSelector\"><div id=\"colorpickerField1\" style=\"background-color: #0000ff\"></div></div>";
 
?>
 
 
<input type='button' onclick='notEmpty()' value='Form Checker' />