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Antiguo 29/04/2003, 12:53
Avatar de Eztopa
Eztopa
 
Fecha de Ingreso: diciembre-2002
Ubicación: En todas partes
Mensajes: 135
Antigüedad: 21 años, 11 meses
Puntos: 0
Saludos caricatos :), he visto tu web y tienes unas caricaturas bastante interesantes.
En efecto, me interesa la segunda opcion, que se pueda visualizar en todos los navegadores.
Este es el codigo que he encontrado:

<script language="JavaScript1.2">
<!--

/*
Gradient Bar Script (By Alex Szorkovszky [email protected])
Permission granted to Dynamicdrive.com to feature script in archive
For full source code and installation instructions to this script, visit http://dynamicdrive.com
*/

if (document.all){
one=new Array();
two=new Array();
var a=10;var b=11;var c=12;var d=13;var e=14;var f=15;


//configure gradient

//width and height of gradient
var width = 640;
var height = 480;

//no of pixels between colours
var gap = 5;

//0 for horizontal, 1 for vertical
var direction = 1;

//colour number 1 - enter 1st, 3rd and 5th numbers/letters of colour code
one[0]=0;
one[1]=0;
one[2]=0;

//colour number 2 - enter 1st, 3rd and 5th numbers/letters of colour code
two[0]=f;
two[1]=f;
two[2]=f;


//end configuration


if(direction==0) var num = width / gap;
if(direction==1) var num = height / gap;
color2=new Array();
color1=new Array();
diff=new Array();
for(i=0;i<3;i++) {
diff[i] = two[i] - one[i];
diff[i] = diff[i] / num;
}
for(i=0;i<3;i++){
color1[i] = Math.round(diff[i] * Math.pow(10, 0));
if(color1[i] > diff[i])color1[i] = color1[i] - 1;
color2[i] = diff[i] - color1[i];
color2[i] = color2[i] * 15;
color2[i] = Math.round(color2[i] * Math.pow(10, 0));
}
x=new Array();
two[0]=0;
two[1]=0;
two[2]=0;
document.write('<table border="0" cellpadding="0" cellspacing="0" width="'+width+'" height="'+height+'">');
if(direction==0) document.write('<tr>');
for(i=0;i<=num;i++) {
if(direction==1) document.write('<tr>');
document.write('<td bgcolor="#');
for(j=0;j<3;j++) {
if(one[j]==a)document.write("a");
if(one[j]==b)document.write("b");
if(one[j]==c)document.write("c");
if(one[j]==d)document.write("d");
if(one[j]==e)document.write("e");
if(one[j]==f)document.write("f");
if(one[j]<10)document.write(one[j]);
if(two[j]==a)document.write("a");
if(two[j]==b)document.write("b");
if(two[j]==c)document.write("c");
if(two[j]==d)document.write("d");
if(two[j]==e)document.write("e");
if(two[j]==f)document.write("f");
if(two[j]<10)document.write(two[j]);
one[j] = one[j] + color1[j];
two[j] = two[j] + color2[j];
if(two[j]>15) {
two[j] = two[j] - 15;
one[j]++;
}
}
if(direction==0) document.write('" width="'+gap+'" height="'+height+'">&nbsp;</td>');
if(direction==1) document.write('" width="'+width+'" height="'+gap+'">&nbsp;</td></tr>');
}
document.write('</table>');
}
//-->
</script>

Ahora lo que me gustaria es que ese gradiente ocupara todo el fondo en direccion vertical, y que se adaptara segun la resolucion de pantalla (1024, 800, etc..)
Si me puedes echar una mano te estaria muy agradecido.
Gracias
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