muchos jquery en una pagina

[kadas99]

Te agradezco la respuesta, y te hago otra pregunta mientras voy haciendo prueba y error jaja

osea que de las 4 jquery que puse

Código HTML:

<script type="text/javascript" src="jquery-1.2.6.min.js"></script>
<script type="text/javascript" src="jquery.bgpos.js"></script>
<script type="text/javascript" src="jquery.min.js"></script>
<script type="text/javascript" src="jquery.galleria.js"></script> 

deberia haber 1 que controle todo? el menu y la galeria?

osea que por decir algo, con una de esas jquery y

Código HTML:

$(document).ready(function(){
		
		$('.gallery_demo_unstyled').addClass('gallery_demo'); // adds new class name to maintain degradability
		
		$('ul.gallery_demo').galleria({
			history   : true, // activates the history object for bookmarking, back-button etc.
			clickNext : true, // helper for making the image clickable
			insert    : '#main_image', // the containing selector for our main image
			onImage   : function(image,caption,thumb) { // let's add some image effects for demonstration purposes
				
				// fade in the image & caption
				image.css('display','none').fadeIn(1000);
				caption.css('display','none').fadeIn(1000);
				
				// fetch the thumbnail container
				var _li = thumb.parents('li');
				
				// fade out inactive thumbnail
				_li.siblings().children('img.selected').fadeTo(500,0.3);
				
				// fade in active thumbnail
				thumb.fadeTo('fast',1).addClass('selected');
				
				// add a title for the clickable image
				image.attr('title','Next image >>');
			},
			onThumb : function(thumb) { // thumbnail effects goes here
				
				// fetch the thumbnail container
				var _li = thumb.parents('li');
				
				// if thumbnail is active, fade all the way.
				var _fadeTo = _li.is('.active') ? '1' : '0.3';
				
				// fade in the thumbnail when finnished loading
				thumb.css({display:'none',opacity:_fadeTo}).fadeIn(1500);
				
				// hover effects
				thumb.hover(
					function() { thumb.fadeTo('fast',1); },
					function() { _li.not('.active').children('img').fadeTo('fast',0.3); } // don't fade out if the parent is active
				)
			}
		});
	});

y

Código HTML:

$(function(){
	$('#a a')
		.css( {backgroundPosition: "-20px 35px"} )
		.mouseover(function(){
			$(this).stop().animate({backgroundPosition:"(-20px 94px)"}, {duration:500})
		})
		.mouseout(function(){
			$(this).stop().animate({backgroundPosition:"(40px 35px)"}, {duration:200, complete:function(){
				$(this).css({backgroundPosition: "-20px 35px"})
			}})
		})
	$('#b a')
		.css( {backgroundPosition: "0 0"} )
		.mouseover(function(){
			$(this).stop().animate({backgroundPosition:"(-150px 0)"}, {duration:500})
		})
		.mouseout(function(){
			$(this).stop().animate({backgroundPosition:"(-300px 0)"}, {duration:200, complete:function(){
				$(this).css({backgroundPosition: "0 0"})
			}})
		})
	$('#c a')
		.css( {backgroundPosition: "0 0"} )
		.mouseover(function(){
			$(this).stop().animate({backgroundPosition:"(0 -250px)"}, {duration:500})
		})
		.mouseout(function(){
			$(this).stop().animate({backgroundPosition:"(0 0)"}, {duration:500})
		})
	$('#d a')
		.css( {backgroundPosition: "0 0"} )
		.mouseover(function(){
			$(this).stop().animate({backgroundPosition:"(0 -250px)"}, {duration:500})
		})
		.mouseout(function(){
			$(this).stop().animate({backgroundPosition:"(0 0)"}, {duration:500})
		})
});

deberia funcionar?

un abrazo