Consulta conflictiva

[flaviovich]

A ver, te doy un avance:

Código SQL:

SELECT C.*
FROM cliente C
INNER JOIN (
    SELECT T1.cliente
    FROM cliente T1
    INNER JOIN contacto T2 ON T1.id=T2.id
    GROUP BY T1.cliente
    HAVING COUNT(DISTINCT admin)>1
) T ON C.id=T.id