leo lo e dejado asip
Código PHP:
<link href="css/css/ext-all.css" rel="stylesheet" type="text/css" />
<?php
include ("../jao/conexion.php");
?>
<?php
$colname_producto = "1";
if (isset($_GET['id_empleado'])) {
$sql = (get_magic_quotes_gpc()) ? $_GET['id_empleado'] : addslashes($_GET['id_empleado']);
}
$db = mysql_connect($server, $dbuser, $dbpass);
$query_producto = sprintf("SELECT * FROM tblempleados WHERE id_empleado = %s", $colname_producto);
$result=mysql_db_query($database,$sql,$db);
while($row = mysql_fetch_array($result))
?>
<div id= id="x-debug-browser">
<? echo $row_producto['categoria']; ?>
</div>
pero me tira un Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\siap\Modulo_RRHH\ver.php on line 14