Multiples If's Anidados

[HackmanC]

Otra forma de hacer lo mismo:
Creo que era lo que "chuidiang" quiso dar a entender...

Código:

package org.example;

public class example {

	public static String arg1;
	public static String arg2;
	public static String arg3;
	public static String arg4;
	
	public static void main(String[] args) {
		int b = 0;
		
		b += assignBit(arg1, 0x1); // bitflags 0001 = 1
		b += assignBit(arg2, 0x2); // bitflags 0010 = 2
		b += assignBit(arg3, 0x4); // bitflags 0100 = 4
		b += assignBit(arg4, 0x8); // bitflags 1000 = 8
		// b += assignBit(argN, 0x10); // bitflags 10000 = 16
		
		switch (b) {
			case 0: // 0             : everything is null
			case 1: // 1             : arg1 != null [others == null]
			case 2: // 2             : arg2 != null [others == null] 
			case 3: // 2 + 1       : arg1 != null and arg2 != null [others == null]
			case 4: // 4             : arg3 != null [otheres == null]
			case 5: // 4 + 1       : arg3 != null and arg1 != null [others == null]
			case 6: // 4 + 2       : arg3 != null and arg2 != null [others == null]
			case 7: // 4 + 2 + 1 : arg1 != null and arg2 != null and arg3 != null [others == null]
			case 8: // 8             : arg4 != null [others == null]
			case 9: // 8 + 1       : arg4 != null and arg1 != null [others == null]
				// etc, etc....
			default:
		}
		
		// OR USE java.util.BitSet in place of [int b]
	}

	public static int assignBit(String arg, int val) {
		if(arg != null) if (!arg.isEmpty()) return val;
		return 0;
	}
	
}